Data.Set.Internal

WARNING

This module is considered internal.

The Package Versioning Policy does not apply.

The contents of this module may change in any way whatsoever and without any warning between minor versions of this package.

Authors importing this module are expected to track development closely.

Description

An efficient implementation of sets.

These modules are intended to be imported qualified, to avoid name clashes with Prelude functions, e.g.

 import Data.Set (Set)
 import qualified Data.Set as Set

The implementation of Set is based on size balanced binary trees (or trees of bounded balance) as described by:

• Stephen Adams, "Efficient sets: a balancing act", Journal of Functional Programming 3(4):553-562, October 1993, http://www.swiss.ai.mit.edu/~adams/BB/.
• J. Nievergelt and E.M. Reingold, "Binary search trees of bounded balance", SIAM journal of computing 2(1), March 1973.

Bounds for union, intersection, and difference are as given by

• Guy Blelloch, Daniel Ferizovic, and Yihan Sun, "Just Join for Parallel Ordered Sets", https://arxiv.org/abs/1602.02120v3.

Note that the implementation is left-biased -- the elements of a first argument are always preferred to the second, for example in union or insert. Of course, left-biasing can only be observed when equality is an equivalence relation instead of structural equality.

Warning: The size of the set must not exceed maxBound::Int. Violation of this condition is not detected and if the size limit is exceeded, the behavior of the set is completely undefined.

Since: 0.5.9

Set type

data Set a

A set of values a.

Constructors

Bin !Size !a !(Set a) !(Set a)

Tip

Instances

Foldable Set

Folds in order of increasing key.

Defined in Data.Set.Internal

Methods

fold :: Monoid m => Set m -> m

foldMap :: Monoid m => (a -> m) -> Set a -> m

foldMap' :: Monoid m => (a -> m) -> Set a -> m

foldr :: (a -> b -> b) -> b -> Set a -> b

foldr' :: (a -> b -> b) -> b -> Set a -> b

foldl :: (b -> a -> b) -> b -> Set a -> b

foldl' :: (b -> a -> b) -> b -> Set a -> b

foldr1 :: (a -> a -> a) -> Set a -> a

foldl1 :: (a -> a -> a) -> Set a -> a

toList :: Set a -> [a]

null :: Set a -> Bool

length :: Set a -> Int

elem :: Eq a => a -> Set a -> Bool

maximum :: Ord a => Set a -> a

minimum :: Ord a => Set a -> a

sum :: Num a => Set a -> a

product :: Num a => Set a -> a

Eq1 Set

Since: 0.5.9

Defined in Data.Set.Internal

Methods

liftEq :: (a -> b -> Bool) -> Set a -> Set b -> Bool

Ord1 Set

Since: 0.5.9

Defined in Data.Set.Internal

Methods

liftCompare :: (a -> b -> Ordering) -> Set a -> Set b -> Ordering

Show1 Set

Since: 0.5.9

Defined in Data.Set.Internal

Methods

liftShowsPrec :: (Int -> a -> ShowS) -> ([a] -> ShowS) -> Int -> Set a -> ShowS

liftShowList :: (Int -> a -> ShowS) -> ([a] -> ShowS) -> [Set a] -> ShowS

Lift a => Lift (Set a :: Type)

@since FIXME

Defined in Data.Set.Internal

Methods

lift :: Set a -> Q Exp

liftTyped :: Set a -> Q (TExp (Set a))

Ord a => IsList (Set a)

Since: 0.5.6.2

Defined in Data.Set.Internal

Associated Types

type Item (Set a)

Methods

fromList :: [Item (Set a)] -> Set a

fromListN :: Int -> [Item (Set a)] -> Set a

toList :: Set a -> [Item (Set a)]

Eq a => Eq (Set a)

Defined in Data.Set.Internal

Methods

(==) :: Set a -> Set a -> Bool

(/=) :: Set a -> Set a -> Bool

(Data a, Ord a) => Data (Set a)

Defined in Data.Set.Internal

Methods

gfoldl :: (forall d b. Data d => c (d -> b) -> d -> c b) -> (forall g. g -> c g) -> Set a -> c (Set a)

gunfold :: (forall b r. Data b => c (b -> r) -> c r) -> (forall r. r -> c r) -> Constr -> c (Set a)

toConstr :: Set a -> Constr

dataTypeOf :: Set a -> DataType

dataCast1 :: Typeable t => (forall d. Data d => c (t d)) -> Maybe (c (Set a))

dataCast2 :: Typeable t => (forall d e. (Data d, Data e) => c (t d e)) -> Maybe (c (Set a))

gmapT :: (forall b. Data b => b -> b) -> Set a -> Set a

gmapQl :: (r -> r' -> r) -> r -> (forall d. Data d => d -> r') -> Set a -> r

gmapQr :: forall r r'. (r' -> r -> r) -> r -> (forall d. Data d => d -> r') -> Set a -> r

gmapQ :: (forall d. Data d => d -> u) -> Set a -> [u]

gmapQi :: Int -> (forall d. Data d => d -> u) -> Set a -> u

gmapM :: Monad m => (forall d. Data d => d -> m d) -> Set a -> m (Set a)

gmapMp :: MonadPlus m => (forall d. Data d => d -> m d) -> Set a -> m (Set a)

gmapMo :: MonadPlus m => (forall d. Data d => d -> m d) -> Set a -> m (Set a)

Ord a => Ord (Set a)

Defined in Data.Set.Internal

Methods

compare :: Set a -> Set a -> Ordering

(<) :: Set a -> Set a -> Bool

(<=) :: Set a -> Set a -> Bool

(>) :: Set a -> Set a -> Bool

(>=) :: Set a -> Set a -> Bool

max :: Set a -> Set a -> Set a

min :: Set a -> Set a -> Set a

(Read a, Ord a) => Read (Set a)

Defined in Data.Set.Internal

Methods

readsPrec :: Int -> ReadS (Set a)

readList :: ReadS [Set a]

readPrec :: ReadPrec (Set a)

readListPrec :: ReadPrec [Set a]

Show a => Show (Set a)

Defined in Data.Set.Internal

Methods

showsPrec :: Int -> Set a -> ShowS

show :: Set a -> String

showList :: [Set a] -> ShowS

Ord a => Semigroup (Set a)

Since: 0.5.7

Defined in Data.Set.Internal

Methods

(<>) :: Set a -> Set a -> Set a

sconcat :: NonEmpty (Set a) -> Set a

stimes :: Integral b => b -> Set a -> Set a

Ord a => Monoid (Set a)

Defined in Data.Set.Internal

Methods

mempty :: Set a

mappend :: Set a -> Set a -> Set a

mconcat :: [Set a] -> Set a

NFData a => NFData (Set a)

Defined in Data.Set.Internal

Methods

rnf :: Set a -> ()

type Item (Set a)

Defined in Data.Set.Internal

type Item (Set a) = a

type Size = Int

Operators

(\\) :: Ord a => Set a -> Set a -> Set a infixl 9

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). See difference.

Query

null :: Set a -> Bool

\(O(1)\). Is this the empty set?

size :: Set a -> Int

\(O(1)\). The number of elements in the set.

member :: Ord a => a -> Set a -> Bool

\(O(\log n)\). Is the element in the set?

notMember :: Ord a => a -> Set a -> Bool

\(O(\log n)\). Is the element not in the set?

lookupLT :: Ord a => a -> Set a -> Maybe a

\(O(\log n)\). Find largest element smaller than the given one.

lookupLT 3 (fromList [3, 5]) == Nothing
lookupLT 5 (fromList [3, 5]) == Just 3

lookupGT :: Ord a => a -> Set a -> Maybe a

\(O(\log n)\). Find smallest element greater than the given one.

lookupGT 4 (fromList [3, 5]) == Just 5
lookupGT 5 (fromList [3, 5]) == Nothing

lookupLE :: Ord a => a -> Set a -> Maybe a

\(O(\log n)\). Find largest element smaller or equal to the given one.

lookupLE 2 (fromList [3, 5]) == Nothing
lookupLE 4 (fromList [3, 5]) == Just 3
lookupLE 5 (fromList [3, 5]) == Just 5

lookupGE :: Ord a => a -> Set a -> Maybe a

\(O(\log n)\). Find smallest element greater or equal to the given one.

lookupGE 3 (fromList [3, 5]) == Just 3
lookupGE 4 (fromList [3, 5]) == Just 5
lookupGE 6 (fromList [3, 5]) == Nothing

isSubsetOf :: Ord a => Set a -> Set a -> Bool

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). (s1 `isSubsetOf` s2) indicates whether s1 is a subset of s2.

s1 `isSubsetOf` s2 = all (`member` s2) s1
s1 `isSubsetOf` s2 = null (s1 `difference` s2)
s1 `isSubsetOf` s2 = s1 `union` s2 == s2
s1 `isSubsetOf` s2 = s1 `intersection` s2 == s1

isProperSubsetOf :: Ord a => Set a -> Set a -> Bool

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). (s1 `isProperSubsetOf` s2) indicates whether s1 is a proper subset of s2.

s1 `isProperSubsetOf` s2 = s1 `isSubsetOf` s2 && s1 /= s2

disjoint :: Ord a => Set a -> Set a -> Bool

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). Check whether two sets are disjoint (i.e., their intersection is empty).

disjoint (fromList [2,4,6])   (fromList [1,3])     == True
disjoint (fromList [2,4,6,8]) (fromList [2,3,5,7]) == False
disjoint (fromList [1,2])     (fromList [1,2,3,4]) == False
disjoint (fromList [])        (fromList [])        == True

xs `disjoint` ys = null (xs `intersection` ys)

Since: 0.5.11

Construction

empty :: Set a

\(O(1)\). The empty set.

singleton :: a -> Set a

\(O(1)\). Create a singleton set.

insert :: Ord a => a -> Set a -> Set a

\(O(\log n)\). Insert an element in a set. If the set already contains an element equal to the given value, it is replaced with the new value.

delete :: Ord a => a -> Set a -> Set a

\(O(\log n)\). Delete an element from a set.

alterF :: (Ord a, Functor f) => (Bool -> f Bool) -> a -> Set a -> f (Set a)

\(O(\log n)\) (alterF f x s) can delete or insert x in s depending on whether an equal element is found in s.

In short:

member x <$> alterF f x s = f (member x s)

Note that unlike insert, alterF will not replace an element equal to the given value.

Note: alterF is a variant of the at combinator from Control.Lens.At.

Since: 0.6.3.1

powerSet :: Set a -> Set (Set a)

Calculate the power set of a set: the set of all its subsets.

t `member` powerSet s == t `isSubsetOf` s

Example:

powerSet (fromList [1,2,3]) =
  fromList $ map fromList [[],[1],[1,2],[1,2,3],[1,3],[2],[2,3],[3]]

Since: 0.5.11

Combine

union :: Ord a => Set a -> Set a -> Set a

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). The union of two sets, preferring the first set when equal elements are encountered.

unions :: (Foldable f, Ord a) => f (Set a) -> Set a

The union of the sets in a Foldable structure : (unions == foldl union empty).

difference :: Ord a => Set a -> Set a -> Set a

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). Difference of two sets.

Return elements of the first set not existing in the second set.

difference (fromList [5, 3]) (fromList [5, 7]) == singleton 3

intersection :: Ord a => Set a -> Set a -> Set a

\(O\bigl(m \log\bigl(\frac{n+1}{m+1}\bigr)\bigr), \; m \leq n\). The intersection of two sets. Elements of the result come from the first set, so for example

import qualified Data.Set as S
data AB = A | B deriving Show
instance Ord AB where compare _ _ = EQ
instance Eq AB where _ == _ = True
main = print (S.singleton A `S.intersection` S.singleton B,
              S.singleton B `S.intersection` S.singleton A)

prints (fromList [A],fromList [B]).

intersections :: Ord a => NonEmpty (Set a) -> Set a

The intersection of a series of sets. Intersections are performed left-to-right.

cartesianProduct :: Set a -> Set b -> Set (a, b)

\(O(mn)\) (conjectured). Calculate the Cartesian product of two sets.

cartesianProduct xs ys = fromList $ liftA2 (,) (toList xs) (toList ys)

Example:

cartesianProduct (fromList [1,2]) (fromList ['a','b']) =
  fromList [(1,'a'), (1,'b'), (2,'a'), (2,'b')]

Since: 0.5.11

disjointUnion :: Set a -> Set b -> Set (Either a b)

Calculate the disjoint union of two sets.

 disjointUnion xs ys = map Left xs `union` map Right ys

Example:

disjointUnion (fromList [1,2]) (fromList ["hi", "bye"]) =
  fromList [Left 1, Left 2, Right "hi", Right "bye"]

Since: 0.5.11

newtype Intersection a

Sets form a Semigroup under intersection.

Constructors

Intersection

Fields

• getIntersection :: Set a

Instances

Eq a => Eq (Intersection a)

Defined in Data.Set.Internal

Methods

(==) :: Intersection a -> Intersection a -> Bool

(/=) :: Intersection a -> Intersection a -> Bool

Ord a => Ord (Intersection a)

Defined in Data.Set.Internal

Methods

compare :: Intersection a -> Intersection a -> Ordering

(<) :: Intersection a -> Intersection a -> Bool

(<=) :: Intersection a -> Intersection a -> Bool

(>) :: Intersection a -> Intersection a -> Bool

(>=) :: Intersection a -> Intersection a -> Bool

max :: Intersection a -> Intersection a -> Intersection a

min :: Intersection a -> Intersection a -> Intersection a

Show a => Show (Intersection a)

Defined in Data.Set.Internal

Methods

showsPrec :: Int -> Intersection a -> ShowS

show :: Intersection a -> String

showList :: [Intersection a] -> ShowS

Ord a => Semigroup (Intersection a)

Defined in Data.Set.Internal

Methods

(<>) :: Intersection a -> Intersection a -> Intersection a

sconcat :: NonEmpty (Intersection a) -> Intersection a

stimes :: Integral b => b -> Intersection a -> Intersection a

Filter

filter :: (a -> Bool) -> Set a -> Set a

\(O(n)\). Filter all elements that satisfy the predicate.

takeWhileAntitone :: (a -> Bool) -> Set a -> Set a

\(O(\log n)\). Take while a predicate on the elements holds. The user is responsible for ensuring that for all elements j and k in the set, j < k ==> p j >= p k. See note at spanAntitone.

takeWhileAntitone p = fromDistinctAscList . takeWhile p . toList
takeWhileAntitone p = filter p

Since: 0.5.8

dropWhileAntitone :: (a -> Bool) -> Set a -> Set a

\(O(\log n)\). Drop while a predicate on the elements holds. The user is responsible for ensuring that for all elements j and k in the set, j < k ==> p j >= p k. See note at spanAntitone.

dropWhileAntitone p = fromDistinctAscList . dropWhile p . toList
dropWhileAntitone p = filter (not . p)

Since: 0.5.8

spanAntitone :: (a -> Bool) -> Set a -> (Set a, Set a)

\(O(\log n)\). Divide a set at the point where a predicate on the elements stops holding. The user is responsible for ensuring that for all elements j and k in the set, j < k ==> p j >= p k.

spanAntitone p xs = (takeWhileAntitone p xs, dropWhileAntitone p xs)
spanAntitone p xs = partition p xs

Note: if p is not actually antitone, then spanAntitone will split the set at some unspecified point where the predicate switches from holding to not holding (where the predicate is seen to hold before the first element and to fail after the last element).

Since: 0.5.8

partition :: (a -> Bool) -> Set a -> (Set a, Set a)

\(O(n)\). Partition the set into two sets, one with all elements that satisfy the predicate and one with all elements that don't satisfy the predicate. See also split.

split :: Ord a => a -> Set a -> (Set a, Set a)

\(O(\log n)\). The expression (split x set) is a pair (set1,set2) where set1 comprises the elements of set less than x and set2 comprises the elements of set greater than x.

splitMember :: Ord a => a -> Set a -> (Set a, Bool, Set a)

\(O(\log n)\). Performs a split but also returns whether the pivot element was found in the original set.

splitRoot :: Set a -> [Set a]

\(O(1)\). Decompose a set into pieces based on the structure of the underlying tree. This function is useful for consuming a set in parallel.

No guarantee is made as to the sizes of the pieces; an internal, but deterministic process determines this. However, it is guaranteed that the pieces returned will be in ascending order (all elements in the first subset less than all elements in the second, and so on).

Examples:

splitRoot (fromList [1..6]) ==
  [fromList [1,2,3],fromList [4],fromList [5,6]]

splitRoot empty == []

Note that the current implementation does not return more than three subsets, but you should not depend on this behaviour because it can change in the future without notice.

Since: 0.5.4

Indexed

lookupIndex :: Ord a => a -> Set a -> Maybe Int

\(O(\log n)\). Lookup the index of an element, which is its zero-based index in the sorted sequence of elements. The index is a number from 0 up to, but not including, the size of the set.

isJust   (lookupIndex 2 (fromList [5,3])) == False
fromJust (lookupIndex 3 (fromList [5,3])) == 0
fromJust (lookupIndex 5 (fromList [5,3])) == 1
isJust   (lookupIndex 6 (fromList [5,3])) == False

Since: 0.5.4

findIndex :: Ord a => a -> Set a -> Int

\(O(\log n)\). Return the index of an element, which is its zero-based index in the sorted sequence of elements. The index is a number from 0 up to, but not including, the size of the set. Calls error when the element is not a member of the set.

findIndex 2 (fromList [5,3])    Error: element is not in the set
findIndex 3 (fromList [5,3]) == 0
findIndex 5 (fromList [5,3]) == 1
findIndex 6 (fromList [5,3])    Error: element is not in the set

Since: 0.5.4

elemAt :: Int -> Set a -> a

\(O(\log n)\). Retrieve an element by its index, i.e. by its zero-based index in the sorted sequence of elements. If the index is out of range (less than zero, greater or equal to size of the set), error is called.

elemAt 0 (fromList [5,3]) == 3
elemAt 1 (fromList [5,3]) == 5
elemAt 2 (fromList [5,3])    Error: index out of range

Since: 0.5.4

deleteAt :: Int -> Set a -> Set a

\(O(\log n)\). Delete the element at index, i.e. by its zero-based index in the sorted sequence of elements. If the index is out of range (less than zero, greater or equal to size of the set), error is called.

deleteAt 0    (fromList [5,3]) == singleton 5
deleteAt 1    (fromList [5,3]) == singleton 3
deleteAt 2    (fromList [5,3])    Error: index out of range
deleteAt (-1) (fromList [5,3])    Error: index out of range

Since: 0.5.4

take :: Int -> Set a -> Set a

Take a given number of elements in order, beginning with the smallest ones.

take n = fromDistinctAscList . take n . toAscList

Since: 0.5.8

drop :: Int -> Set a -> Set a

Drop a given number of elements in order, beginning with the smallest ones.

drop n = fromDistinctAscList . drop n . toAscList

Since: 0.5.8

splitAt :: Int -> Set a -> (Set a, Set a)

\(O(\log n)\). Split a set at a particular index.

splitAt !n !xs = (take n xs, drop n xs)

Map

map :: Ord b => (a -> b) -> Set a -> Set b

\(O(n \log n)\). map f s is the set obtained by applying f to each element of s.

It's worth noting that the size of the result may be smaller if, for some (x,y), x /= y && f x == f y

mapMonotonic :: (a -> b) -> Set a -> Set b

\(O(n)\). The

mapMonotonic f s == map f s, but works only when f is strictly increasing. The precondition is not checked. Semi-formally, we have:

and [x < y ==> f x < f y | x <- ls, y <- ls]
                    ==> mapMonotonic f s == map f s
    where ls = toList s

Folds

foldr :: (a -> b -> b) -> b -> Set a -> b

\(O(n)\). Fold the elements in the set using the given right-associative binary operator, such that foldr f z == foldr f z . toAscList.

For example,

toAscList set = foldr (:) [] set

foldl :: (a -> b -> a) -> a -> Set b -> a

\(O(n)\). Fold the elements in the set using the given left-associative binary operator, such that foldl f z == foldl f z . toAscList.

For example,

toDescList set = foldl (flip (:)) [] set

Strict folds

foldr' :: (a -> b -> b) -> b -> Set a -> b

\(O(n)\). A strict version of foldr. Each application of the operator is evaluated before using the result in the next application. This function is strict in the starting value.

foldl' :: (a -> b -> a) -> a -> Set b -> a

\(O(n)\). A strict version of foldl. Each application of the operator is evaluated before using the result in the next application. This function is strict in the starting value.

Legacy folds

fold :: (a -> b -> b) -> b -> Set a -> b

\(O(n)\). Fold the elements in the set using the given right-associative binary operator. This function is an equivalent of foldr and is present for compatibility only.

Please note that fold will be deprecated in the future and removed.

Min/Max

lookupMin :: Set a -> Maybe a

\(O(\log n)\). The minimal element of a set.

Since: 0.5.9

lookupMax :: Set a -> Maybe a

\(O(\log n)\). The maximal element of a set.

Since: 0.5.9

findMin :: Set a -> a

\(O(\log n)\). The minimal element of a set.

findMax :: Set a -> a

\(O(\log n)\). The maximal element of a set.

deleteMin :: Set a -> Set a

\(O(\log n)\). Delete the minimal element. Returns an empty set if the set is empty.

deleteMax :: Set a -> Set a

\(O(\log n)\). Delete the maximal element. Returns an empty set if the set is empty.

deleteFindMin :: Set a -> (a, Set a)

\(O(\log n)\). Delete and find the minimal element.

deleteFindMin set = (findMin set, deleteMin set)

deleteFindMax :: Set a -> (a, Set a)

\(O(\log n)\). Delete and find the maximal element.

deleteFindMax set = (findMax set, deleteMax set)

maxView :: Set a -> Maybe (a, Set a)

\(O(\log n)\). Retrieves the maximal key of the set, and the set stripped of that element, or Nothing if passed an empty set.

minView :: Set a -> Maybe (a, Set a)

\(O(\log n)\). Retrieves the minimal key of the set, and the set stripped of that element, or Nothing if passed an empty set.

Conversion

List

elems :: Set a -> [a]

\(O(n)\). An alias of toAscList. The elements of a set in ascending order. Subject to list fusion.

toList :: Set a -> [a]

\(O(n)\). Convert the set to a list of elements. Subject to list fusion.

fromList :: Ord a => [a] -> Set a

\(O(n \log n)\). Create a set from a list of elements.

If the elements are ordered, a linear-time implementation is used, with the performance equal to fromDistinctAscList.

Ordered list

toAscList :: Set a -> [a]

\(O(n)\). Convert the set to an ascending list of elements. Subject to list fusion.

toDescList :: Set a -> [a]

\(O(n)\). Convert the set to a descending list of elements. Subject to list fusion.

fromAscList :: Eq a => [a] -> Set a

\(O(n)\). Build a set from an ascending list in linear time. The precondition (input list is ascending) is not checked.

fromDistinctAscList :: [a] -> Set a

\(O(n)\). Build a set from an ascending list of distinct elements in linear time. The precondition (input list is strictly ascending) is not checked.

fromDescList :: Eq a => [a] -> Set a

\(O(n)\). Build a set from a descending list in linear time. The precondition (input list is descending) is not checked.

Since: 0.5.8

fromDistinctDescList :: [a] -> Set a

\(O(n)\). Build a set from a descending list of distinct elements in linear time. The precondition (input list is strictly descending) is not checked.

Debugging

showTree :: Show a => Set a -> String

\(O(n)\). Show the tree that implements the set. The tree is shown in a compressed, hanging format.

showTreeWith :: Show a => Bool -> Bool -> Set a -> String

\(O(n)\). The expression (showTreeWith hang wide map) shows the tree that implements the set. If hang is True, a hanging tree is shown otherwise a rotated tree is shown. If wide is True, an extra wide version is shown.

Set> putStrLn $ showTreeWith True False $ fromDistinctAscList [1..5]
4
+--2
|  +--1
|  +--3
+--5

Set> putStrLn $ showTreeWith True True $ fromDistinctAscList [1..5]
4
|
+--2
|  |
|  +--1
|  |
|  +--3
|
+--5

Set> putStrLn $ showTreeWith False True $ fromDistinctAscList [1..5]
+--5
|
4
|
|  +--3
|  |
+--2
   |
   +--1

valid :: Ord a => Set a -> Bool

\(O(n)\). Test if the internal set structure is valid.

bin :: a -> Set a -> Set a -> Set a

balanced :: Set a -> Bool

link :: a -> Set a -> Set a -> Set a

merge :: Set a -> Set a -> Set a