Copyright | (c) 2007-2014 Dan Doel (c) 2011-2013 Edward Kmett (c) 2014 Roman Cheplyaka (c) 2020-2021 Andrew Lelechenko (c) 2020-2021 Kevin Quick |
---|---|
License | BSD3 |
Maintainer | Andrew Lelechenko <andrew.lelechenko@gmail.com> |
Safe Haskell | Safe |
Language | Haskell2010 |
Adapted from the paper
Backtracking, Interleaving, and Terminating Monad Transformers
by Oleg Kiselyov, Chung-chieh Shan, Daniel P. Friedman, Amr Sabry.
Note that the paper uses MonadPlus
vocabulary
(mzero
and mplus
),
while examples below prefer empty
and <|>
from Alternative
.
Synopsis
- class (Monad m, Alternative m) => MonadLogic m where
- reflect :: Alternative m => Maybe (a, m a) -> m a
Documentation
class (Monad m, Alternative m) => MonadLogic m where Source #
A backtracking, logic programming monad.
msplit :: m a -> m (Maybe (a, m a)) Source #
Attempts to split the computation, giving access to the first result. Satisfies the following laws:
msplit empty == pure Nothing msplit (pure a <|> m) == pure (Just (a, m))
interleave :: m a -> m a -> m a Source #
Fair disjunction. It is possible for a logical computation to have an infinite number of potential results, for instance:
odds = pure 1 <|> fmap (+ 2) odds
Such computations can cause problems in some circumstances. Consider:
two = do x <- odds <|> pure 2 if even x then pure x else empty
>>>
observe two
...never completes...
Such a computation may never consider pure
2
, and
therefore even observe
two
will
never return any results. By
contrast, using interleave
in place of
<|>
ensures fair consideration of both
branches of a disjunction.
fairTwo = do x <- odds `interleave` pure 2 if even x then pure x else empty
>>>
observe fairTwo
2
Note that even with interleave
this computation will never
terminate after returning 2: only the first value can be
safely observed, after which each odd value becomes empty
(equivalent to
Prolog's fail)
which does not stop the evaluation but indicates there is no
value to return yet.
Unlike <|>
, interleave
is not associative:
>>>
let x = [1,2,3]; y = [4,5,6]; z = [7,8,9] :: [Int]
>>>
x `interleave` y
[1,4,2,5,3,6]>>>
(x `interleave` y) `interleave` z
[1,7,4,8,2,9,5,3,6]>>>
y `interleave` z
[4,7,5,8,6,9]>>>
x `interleave` (y `interleave` z)
[1,4,2,7,3,5,8,6,9]
(>>-) :: m a -> (a -> m b) -> m b infixl 1 Source #
Fair conjunction. Similarly to the previous function, consider
the distributivity law, naturally expected from MonadPlus
:
(a <|> b) >>= k = (a >>= k) <|> (b >>= k)
If a
>>=
k
can backtrack arbitrarily many times, b
>>=
k
may never be considered. In logic statements,
"backtracking" is the process of discarding the current
possible solution value and returning to a previous decision
point where a new value can be obtained and tried. For
example:
>>>
do { x <- pure 0 <|> pure 1 <|> pure 2; if even x then pure x else empty } :: [Int]
[0,2]
Here, the x
value can be produced three times, where
<|>
represents the decision points of that
production. The subsequent if
statement specifies
empty
(fail)
if x
is odd, causing it to be discarded and a return
to an <|>
decision point to get the next x
.
The statement "a
>>=
k
can backtrack arbitrarily many
times" means that the computation is resulting in empty
and
that a
has an infinite number of <|>
applications to
return to. This is called a conjunctive computation because
the logic for a
and k
must both succeed (i.e. pure
a value instead of empty
).
Similar to the way interleave
allows both branches of a
disjunctive computation, the >>-
operator takes care to
consider both branches of a conjunctive computation.
Consider the operation:
odds = pure 1 <|> fmap (2 +) odds oddsPlus n = odds >>= \a -> pure (a + n) g = do x <- (pure 0 <|> pure 1) >>= oddsPlus if even x then pure x else empty
>>>
observeMany 3 g
...never completes...
This will never produce any value because all values produced
by the do
program come from the pure
1
driven operation
(adding one to the sequence of odd values, resulting in the
even values that are allowed by the test in the second line),
but the pure
0
input to oddsPlus
generates an infinite
number of empty
failures so the even values generated by
the pure
1
alternative are never seen. Using
interleave
here instead of <|>
does not help due
to the aforementioned distributivity law.
Also note that the do
notation desugars to >>=
bind
operations, so the following would also fail:
do a <- pure 0 <|> pure 1 x <- oddsPlus a if even x then pure x else empty
The solution is to use the >>-
in place of the normal
monadic bind operation >>=
when fairness between
alternative productions is needed in a conjunction of
statements (rules):
h = do x <- (pure 0 <|> pure 1) >>- oddsPlus if even x then pure x else empty
>>>
observeMany 3 h
[2,4,6]
However, a bit of care is needed when using >>-
because,
unlike >>=
, it is not associative. For example:
>>>
let m = [2,7] :: [Int]
>>>
let k x = [x, x + 1]
>>>
let h x = [x, x * 2]
>>>
m >>= (\x -> k x >>= h)
[2,4,3,6,7,14,8,16]>>>
(m >>= k) >>= h -- same as above
[2,4,3,6,7,14,8,16]>>>
m >>- (\x -> k x >>- h)
[2,7,3,8,4,14,6,16]>>>
(m >>- k) >>- h -- central elements are different
[2,7,4,3,14,8,6,16]
This means that the following will be productive:
(pure 0 <|> pure 1) >>- oddsPlus >>- \x -> if even x then pure x else empty
Which is equivalent to
((pure 0 <|> pure 1) >>- oddsPlus) >>- (\x -> if even x then pure x else empty)
But the following will not be productive:
(pure 0 <|> pure 1) >>- (\a -> (oddsPlus a >>- \x -> if even x then pure x else empty))
Since do notation desugaring results in the latter, the
RebindableSyntax
language pragma cannot easily be used
either. Instead, it is recommended to carefully use explicit
>>-
only when needed.
Pruning. Selects one result out of many. Useful for when multiple results of a computation will be equivalent, or should be treated as such.
As an example, here's a way to determine if a number is composite (has non-trivial integer divisors, i.e. not a prime number):
choose = foldr ((<|>) . pure) empty divisors n = do a <- choose [2..n-1] b <- choose [2..n-1] guard (a * b == n) pure (a, b) composite_ v = do _ <- divisors v pure "Composite"
While this works as intended, it actually does too much work:
>>>
observeAll (composite_ 20)
["Composite", "Composite", "Composite", "Composite"]
Because there are multiple divisors of 20, and they can also occur in either order:
>>>
observeAll (divisors 20)
[(2,10), (4,5), (5,4), (10,2)]
Clearly one could just use observe
here to get the first
non-prime result, but if the call to composite
is in the
middle of other logic code then use once
instead.
composite v = do _ <- once (divisors v) pure "Composite"
>>>
observeAll (composite 20)
["Composite"]
Inverts a logic computation. If m
succeeds with at least one value,
lnot
m
fails. If m
fails, then lnot
m
succeeds with the value ()
.
For example, evaluating if a number is prime can be based on the failure to find divisors of a number:
choose = foldr ((<|>) . pure) empty divisors n = do d <- choose [2..n-1] guard (n `rem` d == 0) pure d prime v = do _ <- lnot (divisors v) pure True
>>>
observeAll (prime 20)
[]>>>
observeAll (prime 19)
[True]
Here if divisors
never succeeds, then the lnot
will
succeed and the number will be declared as prime.
ifte :: m a -> (a -> m b) -> m b -> m b Source #
Logical conditional. The equivalent of
Prolog's soft-cut.
If its first argument succeeds at all,
then the results will be fed into the success
branch. Otherwise, the failure branch is taken. The failure
branch is never considered if the first argument has any
successes. The ifte
function satisfies the following laws:
ifte (pure a) th el == th a ifte empty th el == el ifte (pure a <|> m) th el == th a <|> (m >>= th)
For example, the previous prime
function returned nothing
if the number was not prime, but if it should return False
instead, the following can be used:
choose = foldr ((<|>) . pure) empty divisors n = do d <- choose [2..n-1] guard (n `rem` d == 0) pure d prime v = once (ifte (divisors v) (const (pure False)) (pure True))
>>>
observeAll (prime 20)
[False]>>>
observeAll (prime 19)
[True]
Notice that this cannot be done with a simple if-then-else
because divisors
either generates values or it does not, so
there's no "false" condition to check with a simple if
statement.
Instances
MonadLogic [] Source # | |
Monad m => MonadLogic (LogicT m) Source # | |
Defined in Control.Monad.Logic msplit :: LogicT m a -> LogicT m (Maybe (a, LogicT m a)) Source # interleave :: LogicT m a -> LogicT m a -> LogicT m a Source # (>>-) :: LogicT m a -> (a -> LogicT m b) -> LogicT m b Source # once :: LogicT m a -> LogicT m a Source # lnot :: LogicT m a -> LogicT m () Source # ifte :: LogicT m a -> (a -> LogicT m b) -> LogicT m b -> LogicT m b Source # | |
MonadLogic m => MonadLogic (ReaderT e m) Source # | Note that splitting a transformer does not allow you to provide different input to the monadic object returned. For instance, in: let Just (_, rm') = runReaderT (msplit rm) r in runReaderT rm' r'
|
Defined in Control.Monad.Logic.Class msplit :: ReaderT e m a -> ReaderT e m (Maybe (a, ReaderT e m a)) Source # interleave :: ReaderT e m a -> ReaderT e m a -> ReaderT e m a Source # (>>-) :: ReaderT e m a -> (a -> ReaderT e m b) -> ReaderT e m b Source # once :: ReaderT e m a -> ReaderT e m a Source # lnot :: ReaderT e m a -> ReaderT e m () Source # ifte :: ReaderT e m a -> (a -> ReaderT e m b) -> ReaderT e m b -> ReaderT e m b Source # | |
(MonadLogic m, MonadPlus m) => MonadLogic (StateT s m) Source # | See note on splitting above. |
Defined in Control.Monad.Logic.Class msplit :: StateT s m a -> StateT s m (Maybe (a, StateT s m a)) Source # interleave :: StateT s m a -> StateT s m a -> StateT s m a Source # (>>-) :: StateT s m a -> (a -> StateT s m b) -> StateT s m b Source # once :: StateT s m a -> StateT s m a Source # lnot :: StateT s m a -> StateT s m () Source # ifte :: StateT s m a -> (a -> StateT s m b) -> StateT s m b -> StateT s m b Source # | |
(MonadLogic m, MonadPlus m) => MonadLogic (StateT s m) Source # | See note on splitting above. |
Defined in Control.Monad.Logic.Class msplit :: StateT s m a -> StateT s m (Maybe (a, StateT s m a)) Source # interleave :: StateT s m a -> StateT s m a -> StateT s m a Source # (>>-) :: StateT s m a -> (a -> StateT s m b) -> StateT s m b Source # once :: StateT s m a -> StateT s m a Source # lnot :: StateT s m a -> StateT s m () Source # ifte :: StateT s m a -> (a -> StateT s m b) -> StateT s m b -> StateT s m b Source # |